The relation between root mean square speed (vrms) and most probable sped (vp) for the molar mass M of oxygen gas molecule at the temperature of 300 K will be :
Solution
<p>${v_{rms}} = \sqrt {{{3RT} \over M}}$</p>
<p>${v_p} = \sqrt {{{2RT} \over M}}$</p>
<p>$\Rightarrow {v_{rms}} = \sqrt {{3 \over 2}} {v_p}$</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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