Easy MCQ +4 / -1 PYQ · JEE Mains 2022

The relation between root mean square speed (vrms) and most probable sped (vp) for the molar mass M of oxygen gas molecule at the temperature of 300 K will be :

  1. A ${v_{rms}} = \sqrt {{2 \over 3}} {v_p}$
  2. B ${v_{rms}} = \sqrt {{3 \over 2}} {v_p}$ Correct answer
  3. C ${v_{rms}} = {v_p}$
  4. D ${v_{rms}} = \sqrt {{1 \over 3}} {v_p}$

Solution

<p>${v_{rms}} = \sqrt {{{3RT} \over M}}$</p> <p>${v_p} = \sqrt {{{2RT} \over M}}$</p> <p>$\Rightarrow {v_{rms}} = \sqrt {{3 \over 2}} {v_p}$</p>

About this question

Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law

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