If three moles of monoatomic gas $\left(\gamma=\frac{5}{3}\right)$ is mixed with two moles of a diatomic gas $\left(\gamma=\frac{7}{5}\right)$, the value of adiabatic exponent $\gamma$ for the mixture is
Solution
<p>$$\begin{array}{ll}
\mathrm{f}_1=3, & \mathrm{f}_2=5 \\
\mathrm{n}_1=3, & \mathrm{n}_2=2
\end{array}$$</p>
<p>$$\begin{aligned}
& \mathrm{f}_{\text {mixture }}=\frac{\mathrm{n}_1 \mathrm{f}_1+\mathrm{n}_2 \mathrm{f}_2}{\mathrm{n}_1+\mathrm{n}_2}=\frac{9+10}{\mathrm{f}}=\frac{19}{5} \\
& \gamma_{\text {mixture }}=1+\frac{2 \times 5}{19}=\frac{29}{19}=1.52
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Thermodynamic Processes
This question is part of PrepWiser's free JEE Main question bank. 271 more solved questions on Thermodynamics are available — start with the harder ones if your accuracy is >70%.