$N$ moles of a polyatomic gas $(f=6)$ must be mixed with two moles of a monoatomic gas so that the mixture behaves as a diatomic gas. The value of $N$ is :
Solution
<p>$$\mathrm{f}_{\mathrm{eq}}=\frac{\mathrm{n}_1 \mathrm{f}_1+\mathrm{n}_2 \mathrm{f}_2}{\mathrm{n}_1+\mathrm{n}_2}$$</p>
<p>For diatomic gas $\mathrm{f}_{\mathrm{eq}}=5$</p>
<p>$$\begin{aligned}
& 5=\frac{(\mathrm{N})(6)+(2)(3)}{\mathrm{N}+2} \\
& 5 \mathrm{~N}+10=6 \mathrm{~N}+6 \\
& \mathrm{~N}=4
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Thermodynamic Processes
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