The height of victoria falls is 63 m. What is the difference in temperature of water at the top and at the bottom of fall?
[Given 1 cal = 4.2 J and specific heat of water = 1 cal g$-$1 $^\circ$0C$-$1]
Solution
Change in P.E. = Heat energy<br><br>mgh = mS$\Delta$T<br><br>$\Delta$T = ${{gh} \over S}$<br><br>= ${{10 \times 63} \over {4200J/kgC}}$<br><br>= 0.147$^\circ$C
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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