Consider a sample of oxygen behaving like an ideal gas. At 300 K, the ratio of root mean square (rms) velocity to the average velocity of gas molecule would be :
(Molecular weight of oxygen is 32g/mol; R = 8.3 J K$-$1 mol$-$1)
Solution
${V_{rms}} = \sqrt {{{3RT} \over M}}$<br><br>${V_{avg}} = \sqrt {{8 \over \pi }{{RT} \over M}}$<br><br>${{{V_{rms}}} \over {{V_{avg}}}} = \sqrt {{{3\pi } \over 8}}$
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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