Nitrogen gas is at 300oC temperature. The
temperature (in K) at which the rms speed of a
H2 molecule would be equal to the rms speed
of a nitrogen molecule, is _______.
(Molar mass of N2 gas 28 g).
Answer (integer)
40
Solution
V<sub>rms</sub> = $\sqrt {{{3RT} \over M}}$
<br><br>V<sub>N<sub>2</sub></sub> = $\sqrt {{{3R(573)} \over 28}}$
<br><br>V<sub>H<sub>2</sub></sub> = $\sqrt {{{3RT} \over 2}}$
<br><br>Given, V<sub>N<sub>2</sub></sub> = V<sub>H<sub>2</sub></sub>
<br><br>$\sqrt {{{3RT} \over 2}}$ = $\sqrt {{{3R(573)} \over 28}}$
<br><br>$\Rightarrow$ ${T \over 2} = {{573} \over {28}}$
<br><br>$\Rightarrow$ T = 41 K
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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