Easy INTEGER +4 / -1 PYQ · JEE Mains 2020

Nitrogen gas is at 300oC temperature. The temperature (in K) at which the rms speed of a H2 molecule would be equal to the rms speed of a nitrogen molecule, is _______.
(Molar mass of N2 gas 28 g).

Answer (integer) 40

Solution

V<sub>rms</sub> = $\sqrt {{{3RT} \over M}}$ <br><br>V<sub>N<sub>2</sub></sub> = $\sqrt {{{3R(573)} \over 28}}$ <br><br>V<sub>H<sub>2</sub></sub> = $\sqrt {{{3RT} \over 2}}$ <br><br>Given, V<sub>N<sub>2</sub></sub> = V<sub>H<sub>2</sub></sub> <br><br>$\sqrt {{{3RT} \over 2}}$ = $\sqrt {{{3R(573)} \over 28}}$ <br><br>$\Rightarrow$ ${T \over 2} = {{573} \over {28}}$ <br><br>$\Rightarrow$ T = 41 K

About this question

Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law

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