A source supplies heat to a system at the rate of $1000 \mathrm{~W}$. If the system performs work at a rate of $200 \mathrm{~W}$. The rate at which internal energy of the system increases is
Solution
<p>The rate of increase of internal energy of a system can be found using the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system. </p>
<p>In this case, the heat being supplied to the system is 1000 W and the work being done by the system is 200 W. </p>
<p>Therefore, the rate at which the internal energy of the system increases is:</p>
<p>1000 W (heat supplied) - 200 W (work done) = 800 W</p>
<p>So, the correct answer is 800 W.</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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