Easy MCQ +4 / -1 PYQ · JEE Mains 2024

The translational degrees of freedom $\left(f_t\right)$ and rotational degrees of freedom $\left(f_r\right)$ of $\mathrm{CH}_4$ molecule are:

  1. A $f_t=2$ and $f_r=2$
  2. B $f_t=3$ and $f_r=3$ Correct answer
  3. C $f_t=3$ and 4$f_r=2$$
  4. D $f_t=2$ and $f_r=3$

Solution

<p>For non-linear polyatomic molecules, both translational and rotational degree of freedom have same value and is equal to 3.</p>

About this question

Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law

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