"A mixture of hydrogen and oxygen has volume 500 cm3, temperature 300 K, pressure 400 kPa and mass 0.76 g. The ratio of masses of oxygen to hydrogen will be :-"

Question

Accepted Answer

"PV = nRT

400 $\times$ 10³ $\times$ 500 $\times$ 10^$-$6 = n$\left( {{{25} \over 3}} \right)$ (300)

n = ${{2 \over {25}}}$

n = n₁ + n₂

${{2 \over {25}}}$ = ${{{M_1}} \over 2} + {{{M_2}} \over {32}}$

Also, M₁ + M₂ = 0.76 gm

${{{M_2}} \over {{M_1}}} = {{16} \over 3}$"

A mixture of hydrogen and oxygen has volume 500 cm³, temperature 300 K, pressure 400 kPa and mass 0.76 g. The ratio of masses of oxygen to hydrogen will be :-

Solution

About this question

Drill 25 more like these. Every day. Free.

A mixture of hydrogen and oxygen has volume 500 cm3, temperature 300 K, pressure 400 kPa and mass 0.76 g. The ratio of masses of oxygen to hydrogen will be :-

Solution

About this question

More Thermodynamics questions

Drill 25 more like these. Every day. Free.

A mixture of hydrogen and oxygen has volume 500 cm³, temperature 300 K, pressure 400 kPa and mass 0.76 g. The ratio of masses of oxygen to hydrogen will be :-