In a carnot engine, the temperature of reservoir is 527$^\circ$C and that of sink is 200 K. If the work done by the engine when it transfers heat from reservoir to sink is 12000 kJ, the quantity of heat absorbed by the engine from reservoir is ______________ $\times$ 106 J.
Answer (integer)
16
Solution
<p>$\eta = 1 - {{{T_2}} \over {{T_1}}}$</p>
<p>$= 1 - {{200} \over {800}} = {3 \over 4}$</p>
<p>$\therefore$ $\eta = {W \over {{Q_1}}}$</p>
<p>$\Rightarrow {3 \over 4} = {{12000 \times {{10}^3}} \over {{Q_1}}}$</p>
<p>$\Rightarrow {Q_1} = 16 \times {10^6}\,J$</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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