The temperature at which the kinetic energy of oxygen molecules becomes double than its value at $27^{\circ} \mathrm{C}$ is

<p>The kinetic energy of an ideal gas is given by the equation:</p> <p>$KE = \frac{3}{2} kT$</p> <p>where (k) is Boltzmann&#39;s constant and (T) is the absolute temperature in kelvins. Therefore, the kinetic energy of a gas is directly proportional to its temperature. </p> <p>If the kinetic energy doubles, the temperature must also double. The original temperature is given as ($27^\circ C$), which is equal to (300 K) in absolute terms. Therefore, the final temperature ($T_f$) in kelvins is:</p> <p>$T_f = 2 \cdot 300 K = 600 K$</p> <p>Converting this back to degrees Celsius gives:</p> <p>$T_f = 600K - 273 = 327 ^\circ C$</p>