The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be _____________ J. (Given R = 8.31 J/mol.K)
Answer (integer)
7479
Solution
<p>$U = 2\left( {{3 \over 2}R} \right)300$</p>
<p>$= 3 \times 8.31 \times 300$</p>
<p>$= 7479$ J</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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