if the rms speed of oxygen molecules at 0$^\circ$C is 160 m/s, find the rms speed of hydrogen molecules at 0$^\circ$C.
Solution
${V_{rms}} = \sqrt {{{3KT} \over M}}$<br><br>$${{{{({V_{rms}})}_{{O_2}}}} \over {{{({V_{rms}})}_{{H_2}}}}} = \sqrt {{{{M_{{H_2}}}} \over {{M_{{O_2}}}}}} = \sqrt {{2 \over {32}}} $$<br><br>${({V_{rms}})_{{H_2}}} = 4 \times {({V_{rms}})_{{O_2}}}$<br><br>$= 4 \times 160$<br><br>$= 640$ m/s
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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