Match List I with List II

	List I		List II
A.	Isothermal Process	I.	Work done by the gas decreases internal energy
B.	Adiabatic Process	II.	No change in internal energy
C.	Isochoric Process	III.	The heat absorbed goes partly to increase internal energy and partly to do work
D.	Isobaric Process	IV.	No work is done on or by the gas

Choose the correct answer from the options given below :

$\Delta \mathrm{U}=\mathrm{nC}_{\mathrm{v}} \Delta \mathrm{T}$<br/><br/> For isothermal process $\mathrm{T}$ is constant<br/><br/> So $\Delta \mathrm{U}=0$<br/><br/> $\mathrm{A} \longrightarrow \mathrm{II}$<br/><br/> Adiabatic process<br/><br/> $$ \begin{aligned} & \Delta \mathrm{Q}=0 \\\\ & \Delta \mathrm{Q}=\Delta \mathrm{U}+\Delta \mathrm{W} \\\\ & \Delta \mathrm{U}=-\Delta \mathrm{W} \end{aligned} $$<br/><br/> Work done by gas is positive<br/><br/> So $\Delta \mathrm{U}$ is negative<br/><br/> $\text { B } \longrightarrow \text { I }$<br/><br/> For Isochoric process $\Delta \mathrm{W}=0$<br/><br/> $\mathrm{C} \longrightarrow \mathrm{IV}$<br/><br/> For Isobaric process<br/><br/> $$ \begin{aligned} & \Delta \mathrm{W}=\mathrm{P} \Delta \mathrm{V} \neq 0 \\\\ & \Delta \mathrm{U}=\mathrm{nC}_{\mathrm{V}} \Delta \mathrm{T} \neq 0 \end{aligned} $$<br/><br/> Heat absorbed goes partly to increase internal energy and partly to do work.