A Carnot's engine working between 400 K and 800 K has a work output of 1200 J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is :
Solution
$\eta = 1 - {1 \over 2}$<br><br>$\eta = {1 \over 2}$<br><br>${W \over Q} = \eta$<br><br>${{1200} \over Q} = {1 \over 2}$<br><br>$Q = 2400J$
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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