Easy MCQ +4 / -1 PYQ · JEE Mains 2021

A Carnot's engine working between 400 K and 800 K has a work output of 1200 J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is :

  1. A 2400 J Correct answer
  2. B 1600 J
  3. C 1800 J
  4. D 3200 J

Solution

$\eta = 1 - {1 \over 2}$<br><br>$\eta = {1 \over 2}$<br><br>${W \over Q} = \eta$<br><br>${{1200} \over Q} = {1 \over 2}$<br><br>$Q = 2400J$

About this question

Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law

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