Match the ${{{C_P}} \over {{C_V}}}$ ratio for ideal gases with different type of molecules :
| Molecule Type | CP/CV |
|---|---|
| (A) Monatomic | (I) 7/5 |
| (B) Diatomic rigid molecules | (II) 9/7 |
| (C) Diatomic non-rigid molecules | (III) 4/3 |
| (D) Triatomic rigid molecules | (IV) 5/3 |
Solution
$\gamma = {C_p}/{C_v}$<br><br>${\gamma _A} = 1 + {2 \over 3} = 5/3$<br><br>${\gamma _B} = 1 + {2 \over 5} = 7/5$<br><br>${\gamma _C} = 1 + {2 \over 7} = 9/7$<br><br>${\gamma _D} = 1 + {2 \over 6} = 4/3$
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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