7 mol of a certain monoatomic ideal gas undergoes a temperature increase of $40 \mathrm{~K}$ at constant pressure. The increase in the internal energy of the gas in this process is :
(Given $\mathrm{R}=8.3 \,\mathrm{JK}^{-1} \mathrm{~mol}^{-1}$ )
Solution
<p>$\Delta U = n{C_v}\Delta T$</p>
<p>$= 7 \times {{3R} \over 2} \times 40$</p>
<p>$= 3486\,J$</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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