Easy MCQ +4 / -1 PYQ · JEE Mains 2025

Match List - I with List - II.

List - I List - II
(A) Isothermal (I) ΔW (work done) = 0
(B) Adiabatic (II) ΔQ (supplied heat) = 0
(C) Isobaric (III) ΔU (change in internal energy) ≠ 0
(D) Isochoric (IV) ΔU = 0

Choose the correct answer from the options given below :

  1. A <p>(A)-(III), (B)-(II), (C)-(I), (D)-(IV)</p>
  2. B <p>(A)-(II), (B)-(IV), (C)-(I), (D)-(III)</p>
  3. C <p>(A)-(IV), (B)-(II), (C)-(III), (D)-(I)</p> Correct answer
  4. D <p>(A)-(IV), (B)-(I), (C)-(III), (D)-(II)</p>

Solution

<p>To accurately match the terms from List-I with the corresponding statements in List-II, consider the properties of each thermodynamic process:</p> <p><p><strong>Isothermal Process (A)</strong>: </p></p> <p><p>During an isothermal process, the temperature remains constant ($ \Delta T = 0 $), which means that the change in internal energy ($ \Delta U $) is zero. Therefore, it corresponds to (IV).</p></p> <p><p><strong>Adiabatic Process (B)</strong>: </p></p> <p><p>In an adiabatic process, no heat is exchanged with the surroundings ($ \Delta Q = 0 $). This matches with (II).</p></p> <p><p><strong>Isobaric Process (C)</strong>: </p></p> <p><p>An isobaric process involves constant pressure conditions ($ \Delta P = 0 $), but internal energy ($ \Delta U $) can change. Thus, it's associated with (III).</p></p> <p><p><strong>Isochoric Process (D)</strong>: </p></p> <p><p>For an isochoric process, volume remains constant ($ \Delta V = 0 $), which means that no work is done ($ \Delta W = 0 $). This aligns with (I).</p></p> <p>Based on these descriptions, the correct matching is:</p> <p><p>(A) Isothermal → (IV)</p></p> <p><p>(B) Adiabatic → (II)</p></p> <p><p>(C) Isobaric → (III)</p></p> <p><p>(D) Isochoric → (I)</p></p>

About this question

Subject: Physics · Chapter: Thermodynamics · Topic: Thermodynamic Processes

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