The number of molecules in one litre of an ideal gas at 300 K and 2 atmospheric pressure with mean kinetic energy 2 $\times$ 10$-$9 J per molecules is :
Solution
KE = ${3 \over 2}kT$<br><br>PV = ${N \over {{N_A}}}RT$<br><br>N = ${{PV} \over {kT}}$<br><br>= N = 1.5 $\times$ 10<sup>11</sup>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
This question is part of PrepWiser's free JEE Main question bank. 271 more solved questions on Thermodynamics are available — start with the harder ones if your accuracy is >70%.