One mole of an ideal gas is taken through an adiabatic process where the temperature rises from 27$^\circ$ C to 37$^\circ$ C. If the ideal gas is composed of polyatomic molecule that has 4 vibrational modes, which of the following is true? [R = 8.314 J mol$-$1 k$-$1]
Solution
Since, each vibrational mode, corresponds to two degrees of freedom, hence, f = 3 (trans.) + 3 (rot.) + 4 $\times$ 2 (vib.) = 14<br><br> & $\gamma = 1 + {2 \over f}$<br><br>$\gamma = 1 + {2 \over {14}} = {8 \over 7}$<br><br>$W = {{nR\Delta T} \over {\gamma - 1}} = - 582$<br><br>As W < 0. work is done on the gas.
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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