Molecules of an ideal gas are known to have three translational degrees of freedom and two
rotational degrees of freedom.The gas is maintained at a temperature of T. The total internal
energy, U of a mole of this gas, and the value of
$\gamma \left( { = {{{C_p}} \over {{C_v}}}} \right)$ are given, respectively by:
Solution
Total degree of freedom (f) = 3 + 2 = 5
<br><br>U = ${{nfRT} \over 2}$ = ${{5RT} \over 2}$
<br><br>$\gamma$ = ${{{C_p}} \over {{C_v}}}$ = $1 + {2 \over f}$ = $1 + {2 \over 5}$ = ${7 \over 5}$
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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