Medium MCQ +4 / -1 PYQ · JEE Mains 2021

A refrigerator consumes an average 35W power to operate between temperature $-$10$^\circ$C to 25$^\circ$C. If there is no loss of energy then how much average heat per second does it transfer?

  1. A 263 J/s Correct answer
  2. B 298 J/s
  3. C 350 J/s
  4. D 35 J/s

Solution

$${{{T_L}} \over {{T_H} - {T_L}}} = C.O.P. = {{{{dH} \over {dt}}} \over {{{dW} \over {dt}}}}$$<br><br>${{263} \over {35}} \times 35 = {{dH} \over {dt}}$<br><br>${{dH} \over {dt}} = 263$ watts

About this question

Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law

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