"At 300 K, the rms speed of oxygen molecules is $\sqrt {{{\alpha + 5} \over \alpha }}$ times to that of its average speed in the gas. Then, the value of $\alpha$ will be (used $\pi = {{22} \over 7}$)"

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Accepted Answer

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${v_{rms}} = \sqrt {{{\alpha + 5} \over \alpha }} {v_{avg}}$

$$\sqrt {{{3RT} \over m}} = \sqrt {{{\alpha + 5} \over 5}} \sqrt {{{8RT} \over {\pi m}}} $$

${{3 \times \pi } \over 8} = {{\alpha + 5} \over \alpha }$

${{33} \over {28}} = {{\alpha + 5} \over \alpha }$

$\alpha = 28$

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At 300 K, the rms speed of oxygen molecules is $\sqrt {{{\alpha + 5} \over \alpha }}$ times to that of its average speed in the gas. Then, the value of $\alpha$ will be

(used $\pi = {{22} \over 7}$)

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At 300 K, the rms speed of oxygen molecules is $\sqrt {{{\alpha + 5} \over \alpha }}$ times to that of its average speed in the gas. Then, the value of $\alpha$ will be (used $\pi = {{22} \over 7}$)

Solution

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More Thermodynamics questions

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At 300 K, the rms speed of oxygen molecules is $\sqrt {{{\alpha + 5} \over \alpha }}$ times to that of its average speed in the gas. Then, the value of $\alpha$ will be

(used $\pi = {{22} \over 7}$)