Medium INTEGER +4 / -1 PYQ · JEE Mains 2022

A unit scale is to be prepared whose length does not change with temperature and remains $20 \mathrm{~cm}$, using a bimetallic strip made of brass and iron each of different length. The length of both components would change in such a way that difference between their lengths remains constant. If length of brass is $40 \mathrm{~cm}$ and length of iron will be __________ $\mathrm{cm}$. $\left(\alpha_{\text {iron }}=1.2 \times 10^{-5} \mathrm{~K}^{-1}\right.$ and $\left.\alpha_{\text {brass }}=1.8 \times 10^{-5} \mathrm{~K}^{-1}\right)$.

Answer (integer) 60

Solution

<p>$\Delta {L_1} = {\alpha _1}{L_1}\Delta T$</p> <p>$\Delta {L_2} = {\alpha _2}{L_2}\Delta T$</p> <p>${\alpha _1}{L_1} = {\alpha _2}{L_2}$</p> <p>$1.2 \times {10^{ - 5}} \times {L_1} = 1.8 \times {10^{ - 5}} \times {L_2}$</p> <p>${L_1} = {{1.8} \over {1.2}} \times 40 = 60$ cm</p>

About this question

Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law

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