Medium MCQ +4 / -1 PYQ · JEE Mains 2023

Heat energy of 184 kJ is given to ice of mass 600 g at $-12^\circ \mathrm{C}$. Specific heat of ice is $\mathrm{2222.3~J~kg^{-1^\circ}~C^{-1}}$ and latent heat of ice in 336 $\mathrm{kJ/kg^{-1}}$

A. Final temperature of system will be 0$^\circ$C.

B. Final temperature of the system will be greater than 0$^\circ$C.

C. The final system will have a mixture of ice and water in the ratio of 5 : 1.

D. The final system will have a mixture of ice and water in the ratio of 1 : 5.

E. The final system will have water only.

Choose the correct answer from the options given below :

  1. A A and E only
  2. B B and D only
  3. C A and C only
  4. D A and D only Correct answer

Solution

<p>Heat required to raise the temperature of ice to 0$^\circ$C is</p> <p>$= {{60} \over {1000}}(2222.3)(12)$</p> <p>$= 16000.5$ J</p> <p>$\approx 16$ kJ</p> <p>Heat required to melt ice completely</p> <p>$= \left( {{{600} \over {1000}}} \right)(336)$ kJ</p> <p>$= 201.6$ kJ</p> <p>Energy left $= (184 - 16) = 168$ kJ</p> <p>$\therefore$ Partial ice will melt</p> <p>$\therefore$ $168 = ({m_{ice\,melted}})336$</p> <p>$0.5$ kg $= ({m_{ice\,melted}})$</p> <p>$\therefore$ ${m_{ice}}:{m_{water}} = 1:5$</p>

About this question

Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law

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