An ideal gas is expanding such that PT3 = constant. The coefficient of volume expansion of the gas is :
Solution
PT<sup>3</sup> = constant<br><br>$\left( {{{nRT} \over v}} \right)$T<sup>3</sup> = constant<br><br>T<sup>4</sup> V<sup>$-$1</sup> = constant<br><br>T<sup>4</sup> = kV<br><br>$\Rightarrow 4{{\Delta T} \over T} = {{\Delta V} \over V}$ ....... (1)<br><br>$\Delta$V = V$\gamma$$\Delta$T ........ (2)<br><br>comparing (1) and (2), we get<br><br>$\gamma = {4 \over T}$
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
This question is part of PrepWiser's free JEE Main question bank. 271 more solved questions on Thermodynamics are available — start with the harder ones if your accuracy is >70%.