A 100 g of iron nail is hit by a 1.5 kg hammer striking at a velocity of 60 ms$-$1. What will be the rise in the temperature of the nail if one fourth of energy of the hammer goes into heating the nail?
[Specific heat capacity of iron = 0.42 Jg$-$1 $^\circ$C$-$1]
Solution
<p>$${1 \over 2} \times 1.5 \times {60^2} \times {1 \over 4} = 100 \times 0.42 \times \Delta T$$</p>
<p>$$\Delta T = {{1.5 \times {{60}^2}} \over {8 \times 100 \times 0.42}} = 16.07^\circ C$$</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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