For a gas CP $-$ CV = R in a state P and CP $-$ CV = 1.10 R in a state Q, TP and TQ are the temperatures in two different states P and Q respectively. Then
Solution
C<sub>P</sub> $-$ C<sub>V</sub> = R for ideal gas and gas behaves as ideal gas at high temperature, so T<sub>P</sub> > T<sub>Q</sub>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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