A cylindrical container of volume 4.0 $\times$ 10$-$3 m3 contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is 400 K. The pressure of the mixture of gases is :
[Take gas constant as 8.3 J mol$-$1 K$-$1]
Solution
V = 4 $\times$ 10<sup>$-$3</sup> m<sup>3</sup><br><br>n = 3 moles<br><br>T = 400 K<br><br>PV = nRT $\Rightarrow$ P = ${{nRT} \over V}$<br><br>P = ${{3 \times 8.3 \times 400} \over {4 \times {{10}^{ - 3}}}}$<br><br>= 24.9 $\times$ 10<sup>5</sup> Pa
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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