The specific heat at constant pressure of a real gas obeying $P V^2=R T$ equation is:
Solution
<p>$$\begin{aligned}
& \because \quad P V^2=R T \\
& P(2 v d v)+V^2(d P)=R d T
\end{aligned}$$</p>
<p>at $P=$ const.</p>
<p>$P d v=\frac{R d T}{2 V} \quad \text{... (i)}$</p>
<p>Now, for $n=1$</p>
<p>$$\begin{aligned}
& d \theta=d v+d w \\
& C_P d T=C_v d T+P d v \quad \text{... (ii)}
\end{aligned}$$</p>
<p>from (i) and (ii)</p>
<p>$C_P=C_V+\frac{R}{2 V}$</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Thermodynamic Processes
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