A copper block of mass 5.0 kg is heated to a temperature of 500$^\circ$C and is placed on a large ice block. What is the maximum amount of ice that can melt? [Specific heat of copper : 0.39 J g$-$1 $^\circ$C$-$1 and latent heat of fusion of water : 335 J g$-$1]
Solution
<p>$mL = \Delta Q = ms\Delta T$</p>
<p>$\Rightarrow m = {{5 \times 0.39 \times {{10}^3} \times 500} \over {335}}$</p>
<p>$= 2.9$ kg</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
This question is part of PrepWiser's free JEE Main question bank. 271 more solved questions on Thermodynamics are available — start with the harder ones if your accuracy is >70%.