Given below are two statements :
Statement I : The average momentum of a molecule in a sample of an ideal gas depends on temperature.
Statement II : The rms speed of oxygen molecules in a gas is $v$. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become $2 v$.
In the light of the above statements, choose the correct answer from the options given below :
Solution
<p>Average momentum $= \left\langle {\overrightarrow P } \right\rangle = 0$</p>
<p>${v_{rms}} = \sqrt {{{3RT} \over M}}$</p>
<p>If temperature is doubled and oxygen atoms are used then</p>
<p>$v{'_{rms}} = \sqrt {{{3R(2T)} \over {M/2}}} = 4\,{v_{rms}}$</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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