A Carnot engine takes 5000 kcal of heat from a reservoir at 727$^\circ$C and gives heat to a sink at 127$^\circ$C. The work done by the engine is
Solution
<p>Efficiency $\eta = 1 - {{{T_L}} \over {{T_H}}}$</p>
<p>$= 1 - {{400} \over {1000}} = 0.6$</p>
<p>$\Rightarrow 0.6 = {W \over Q}$</p>
<p>$\Rightarrow W = 0.6Q = 3000$ kcal $=12.6 \times {10^6}$ J</p>
About this question
Subject: Physics · Chapter: Thermodynamics · Topic: Zeroth and First Law
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