JEE Main Rotational Motion Questions & Solutions
15 solved questions on Rotational Motion, ranging from easy to JEE-Advanced-flavour hard. Click any to see the full solution.
15 solved questions on Rotational Motion, ranging from easy to JEE-Advanced-flavour hard. Click any to see the full solution.
A skater has moment of inertia 5 kg·m² spinning at 4 rad/s. She pulls her arms in, reducing $I$ to 2 kg·m². Her new angular speed in rad/s is:
View solution →An ice skater rotating with arms extended pulls them in. Her moment of inertia decreases; her angular speed:
View solution →Angular momentum of a system is conserved when:
View solution →In pure rolling motion, the point of contact of the body with the surface has zero instantaneous velocity.
View solution →A solid cylinder rolls without slipping. The ratio of translational KE to the total KE is:
View solution →For pure rolling without slipping of a wheel of radius $R$:
View solution →A force of 10 N is applied tangentially at a point 0.5 m from the axis of a wheel. The torque is:
View solution →The angular momentum of a particle of mass $m$ moving with velocity $v$ at perpendicular distance $d$ from a fixed axis is:
View solution →The rotational analogue of Newton's second law ($\tau = I\alpha$) corresponds to:
View solution →The radius of gyration has the dimensions of length.
View solution →The moment of inertia of a thin ring of mass $M$ and radius $R$ about an axis through its centre and perpendicular to its plane is:
View solution →The moment of inertia of a solid sphere of mass $M$ and radius $R$ about an axis through its diameter is:
View solution →Two masses 1 kg and 3 kg are placed 4 m apart. The distance (in m) of the centre of mass from the 1 kg mass is:
View solution →Two point masses 2 kg and 3 kg are placed at $x = 0$ and $x = 5$ m respectively. The $x$-coordinate of their centre of mass is:
View solution →The centre of mass of a uniform thin rod lies at:
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