Medium MCQ +4 / -1

The angular momentum of a particle of mass $m$ moving with velocity $v$ at perpendicular distance $d$ from a fixed axis is:

  1. A $mvd$ Correct answer
  2. B $mv/d$
  3. C $mv^2$
  4. D $m/d$

Solution

$L = mvr_{\perp} = mvd$.

About this question

Subject: Physics · Chapter: Rotational Motion · Topic: Torque and Angular Momentum

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