A skater has moment of inertia 5 kg·m² spinning at 4 rad/s. She pulls her arms in, reducing $I$ to 2 kg·m². Her new angular speed in rad/s is:
Answer (integer)
10
Solution
$I_1\omega_1 = I_2\omega_2 \Rightarrow 5 \times 4 = 2 \times \omega_2 \Rightarrow \omega_2 = 10$ rad/s.
About this question
Subject: Physics · Chapter: Rotational Motion · Topic: Conservation of Angular Momentum
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