Easy MCQ +4 / -1

The moment of inertia of a solid sphere of mass $M$ and radius $R$ about an axis through its diameter is:

  1. A $\frac{1}{2}MR^2$
  2. B $\frac{2}{3}MR^2$
  3. C $\frac{2}{5}MR^2$ Correct answer
  4. D $MR^2$

Solution

Standard result: $I_{sphere} = \frac{2}{5}MR^2$ about diameter.

About this question

Subject: Physics · Chapter: Rotational Motion · Topic: Moment of Inertia

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