A particle executes simple harmonic motion between $x=-A$ and $x=+A$. If time taken by particle to go from $x=0$ to $\frac{A}{2}$ is 2 s; then time taken by particle in going from $x=\frac{A}{2}$ to A is
Solution
$x=A \sin (\omega t)$
<br/><br/>
$$
\begin{aligned}
& x=\frac{A}{2}=A \sin (\omega t) \\\\
& \frac{1}{2}=\sin (\omega t) \\\\
& t=\left(\frac{\pi}{6 \omega}\right)=2 \\\\
& \frac{\pi}{\omega}=12 \sec
\end{aligned}
$$
<br/><br/>
$x=A=A \sin (\omega t)$
<br/><br/>
$\omega t=\left(\frac{\pi}{2}\right)$
<br/><br/>
$t=\left(\frac{\pi}{2 \omega}\right)=6$ second
<br/><br/>
time $=6-2=4$ seconds
About this question
Subject: Physics · Chapter: Oscillations · Topic: Simple Harmonic Motion
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