The motion of a simple pendulum executing S.H.M. is represented by the following equation.
$y = A\sin (\pi t + \phi )$, where time is measured in second. The length of pendulum is
Solution
<p>$\omega = \pi = \sqrt {{g \over l}}$</p>
<p>So, $l = {g \over {{\pi ^2}}}$</p>
<p>$\simeq 99.4$ cm (Nearest value)</p>
About this question
Subject: Physics · Chapter: Oscillations · Topic: Simple Harmonic Motion
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