The displacement of simple harmonic oscillator after 3 seconds starting from its mean position is equal to half of its amplitude. The time period of harmonic motion is :
Solution
<p>Time taken by the harmonic oscillator to move from mean position to half of amplitude is ${T \over {12}}$</p>
<p>So, ${T \over {12}}$ = 3</p>
<p>T = 36 sec.</p>
About this question
Subject: Physics · Chapter: Oscillations · Topic: Simple Harmonic Motion
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