Easy MCQ +4 / -1 PYQ · JEE Mains 2021

For what value of displacement the kinetic energy and potential energy of a simple harmonic oscillation become equal ?

  1. A x = ${A \over 2}$
  2. B x = $\pm$ A
  3. C x = $\pm$ ${A \over {\sqrt 2 }}$ Correct answer
  4. D x = 0

Solution

KE = PE<br><br>${1 \over 2}k({A^2} - {X^2}) = {1 \over 2}K{X^2}$<br><br>$\Rightarrow$ ${A^2} - {X^2} = {X^2}$<br><br>$\Rightarrow$ $2{X^2} = {A^2}$<br><br>$\Rightarrow$ ${X^2} = {{{A^2}} \over {\sqrt 2 }}$<br><br>$\Rightarrow$ $X = \pm {A \over {\sqrt 2 }}$

About this question

Subject: Physics · Chapter: Oscillations · Topic: Simple Harmonic Motion

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