In a simple harmonic oscillation, what fraction of total mechanical energy is in the form of kinetic energy, when the particle is midway between mean and extreme position.
Solution
$K = {1 \over 2}m{\omega ^2}({A^2} - {x^2})$<br><br>$= {1 \over 2}m{\omega ^2}\left( {{A^2} - {{{A^2}} \over 4}} \right)$<br><br>$= {1 \over 2}m{\omega ^2}\left( {{{3{A^2}} \over 4}} \right)$<br><br>$K = {3 \over 4}\left( {{1 \over 2}m{\omega ^2}{A^2}} \right)$
About this question
Subject: Physics · Chapter: Oscillations · Topic: Simple Harmonic Motion
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