A particle executes simple harmonic motion. Its amplitude is 8 cm and time period is 6 s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is ___________ s.
Answer (integer)
1
Solution
<p>A = 8 cm</p>
<p>T = 6 s</p>
<p>$A\cos \left( {{{2\pi t} \over T}} \right) = {A \over 2}$</p>
<p>$\Rightarrow {{2\pi t} \over T} = {\pi \over 3}$</p>
<p>or $t = {T \over 6} = 1\,s$</p>
About this question
Subject: Physics · Chapter: Oscillations · Topic: Simple Harmonic Motion
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