A mass m attached to free end of a spring executes SHM with a period of 1s. If the mass is increased by 3 kg the period of the oscillation increases by one second, the value of mass m is ___________ kg.
Answer (integer)
1
Solution
$\because 2 \pi \sqrt{\frac{m}{k}}=1$
<br/><br/>
Finally
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$2 \pi \sqrt{\frac{m+3}{k}}=1+1=2$
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Equation $\frac{(1)}{(2)}$ gives
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$\sqrt{\frac{m}{m+3}}=\frac{1}{2}$
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$\therefore m=1 \mathrm{~kg}$
About this question
Subject: Physics · Chapter: Oscillations · Topic: Simple Harmonic Motion
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