When a particle executes Simple Hormonic Motion, the nature of graph of velocity as a function of displacement will be :
Solution
<p>Let $x = A\sin \omega t$</p>
<p>$\Rightarrow v = A\omega \cos \omega t$</p>
<p>$\Rightarrow v = \, \pm \,\omega \sqrt {{A^2} - {x^2}}$</p>
<p>$\Rightarrow {{{v^2}} \over {{\omega ^2}}} + {x^2} = {A^2}$</p>
<p>$\Rightarrow$ Ellipse</p>
About this question
Subject: Physics · Chapter: Oscillations · Topic: Simple Harmonic Motion
This question is part of PrepWiser's free JEE Main question bank. 88 more solved questions on Oscillations are available — start with the harder ones if your accuracy is >70%.