Two simple harmonic motions are represented by the equations
${x_1} = 5\sin \left( {2\pi t + {\pi \over 4}} \right)$ and ${x_2} = 5\sqrt 2 (\sin 2\pi t + \cos 2\pi t)$. The amplitude of second motion is ................ times the amplitude in first motion.
Answer (integer)
2
Solution
$${x_2} = 5\sqrt 2 \left( {{1 \over {\sqrt 2 }}\sin 2\pi t + {1 \over {\sqrt 2 }}\cos 2\pi t} \right)\sqrt 2 $$<br><br>$= 10\sin \left( {2\pi t + {\pi \over 4}} \right)$<br><br>$\therefore$ ${{{A_2}} \over {{A_1}}} = {{10} \over 5} = 2$
About this question
Subject: Physics · Chapter: Oscillations · Topic: Simple Harmonic Motion
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