A transformer operating at primary voltage $8 \,\mathrm{kV}$ and secondary voltage $160 \mathrm{~V}$ serves a load of $80 \mathrm{~kW}$. Assuming the transformer to be ideal with purely resistive load and working on unity power factor, the loads in the primary and secondary circuit would be
Solution
<p>${V_1}{i_1} = {V_2}{i_2} = 80$ kW</p>
<p>$\Rightarrow {i_1} = 10\,A$ and ${i_2} = {{80 \times 1000} \over {160}} = 500\,A$</p>
<p>$\Rightarrow {R_1} = {{{V_1}} \over {{i_1}}} = 800\,\Omega$ and ${R_2} = {{160} \over {500}} = 0.32\,\Omega$</p>
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
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