An AC voltage $V=20 \sin 200 \pi t$ is applied to a series LCR circuit which drives a current $I=10 \sin \left(200 \pi t+\frac{\pi}{3}\right)$. The average power dissipated is:
Solution
<p>$$\begin{aligned}
& <\mathrm{P}>=\mathrm{IV} \cos \phi \\
& =\frac{20}{\sqrt{2}} \times \frac{10}{\sqrt{2}} \times \cos 60^{\circ} \\
& =50 \mathrm{~W}
\end{aligned}$$</p>
About this question
Subject: Physics · Chapter: Alternating Current · Topic: Power in AC Circuits
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