For a series LCR circuit with R = 100 $\Omega$, L = 0.5 mH and C = 0.1 pF connected across 220V$-$50 Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is :
Solution
R = 100$\Omega$<br><br>${X_L} = \omega L = 50\pi \times {10^{ - 3}}$<br><br>${X_C} = {1 \over {\omega C}} = {{{{10}^{11}}} \over {100\pi }}$<br><br>${X_C} > > {X_L}$<br><br>& $\left| {{X_C} - {X_L}} \right| > > R$
About this question
Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C
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