Easy MCQ +4 / -1 PYQ · JEE Mains 2021

For a series LCR circuit with R = 100 $\Omega$, L = 0.5 mH and C = 0.1 pF connected across 220V$-$50 Hz AC supply, the phase angle between current and supplied voltage and the nature of the circuit is :

  1. A 0$^\circ$, resistive circuit
  2. B $\approx$ 90$^\circ$, predominantly inductive circuit
  3. C 0$^\circ$, resonance circuit
  4. D $\approx$ 90$^\circ$, predominantly capacitive circuit Correct answer

Solution

R = 100$\Omega$<br><br>${X_L} = \omega L = 50\pi \times {10^{ - 3}}$<br><br>${X_C} = {1 \over {\omega C}} = {{{{10}^{11}}} \over {100\pi }}$<br><br>${X_C} &gt; &gt; {X_L}$<br><br>&amp; $\left| {{X_C} - {X_L}} \right| &gt; &gt; R$

About this question

Subject: Physics · Chapter: Alternating Current · Topic: AC Circuits: R, L, C

This question is part of PrepWiser's free JEE Main question bank. 115 more solved questions on Alternating Current are available — start with the harder ones if your accuracy is >70%.

Drill 25 more like these. Every day. Free.

PrepWiser turns these solved questions into a daily practice loop. Chapter-wise drills, full mocks, AI doubt chat. No auto-renew.

Start free →