An ideal transformer with purely resistive load operates at $12 ~\mathrm{kV}$ on the primary side. It supplies electrical energy to a number of nearby houses at $120 \mathrm{~V}$. The average rate of energy consumption in the houses served by the transformer is 60 $\mathrm{kW}$. The value of resistive load $(\mathrm{Rs})$ required in the secondary circuit will be ___________ $\mathrm{m} \Omega$.

<p>The power delivered to the houses is given as 60 kW. This power is supplied at a voltage of 120 V. The power consumed in a resistive load can be found using the formula $P = V^2/R$, where P is the power, V is the voltage, and R is the resistance. </p> <p>We can rearrange this formula to solve for the resistance:</p> <p>$R = V^2/P$</p> <p>Substituting the given values gives:</p> <p>$R = (120 \, \text{V})^2 / 60,000 \, \text{W} = 0.24 \, \Omega$</p> <p>Since we want the resistance in milliohms (mΩ), we can convert this to milliohms by multiplying by 1000:</p> <p>$R = 0.24 \, \Omega \times 1000 = 240 \, m\Omega$</p> <p>So, the value of resistive load required in the secondary circuit is 240 mΩ.</p>